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Algebra I to AP Precalculus · Module 2 of 14

Solving Linear Equations

Isolating a variable through one-step, multi-step, literal, and absolute value equations.

One-Step and Two-Step Equations

  • Use inverse operations to isolate the variable, undoing addition/subtraction before multiplication/division (reverse order of operations).
  • Whatever operation you apply to one side of the equation, apply to the other side too, to keep it balanced.
  • Check your solution by substituting it back into the original equation.
Worked example

Solve 2x + 5 = 17.

Solution. Subtract 5 from both sides: 2x = 12. Divide both sides by 2: x = 6. Check: 2(6) + 5 = 17 ✓.

Multi-Step Equations (Variables on Both Sides)

  • Distribute and combine like terms on each side separately first.
  • Move all variable terms to one side (by adding/subtracting) and all constants to the other.
  • Divide by the coefficient of the variable to finish.
Worked example

Solve 3(x − 2) = 2x + 4.

Solution. Distribute: 3x − 6 = 2x + 4. Subtract 2x: x − 6 = 4. Add 6: x = 10. Check: 3(8) = 24 = 2(10) + 4 ✓.

Common mistake: Distribute before combining or moving terms — combining across the equals sign too early causes sign errors.

Literal Equations & Formulas

  • A literal equation has more than one variable; solve for one variable "in terms of" the others using the same inverse-operation steps.
  • Treat every other variable as if it were a constant number while you isolate the one you want.
Worked example

Solve for h: A = (1/2)bh (area of a triangle).

Solution. Multiply both sides by 2: 2A = bh. Divide both sides by b: h = 2A/b.

Solving Absolute Value Equations

  • |x| = a (a > 0) means x is a units from 0, so it splits into two equations: x = a or x = −a.
  • Isolate the absolute value expression completely before splitting into the two cases.
  • If a is negative, |expression| = a has no solution, since absolute value can never be negative.
Worked example

Solve |2x − 3| = 7.

Solution. Split into two cases: 2x − 3 = 7 → x = 5, or 2x − 3 = −7 → x = −2. Solutions: x = 5 or x = −2.

Common mistake: Isolate the absolute value bars completely (undo anything added outside them) before splitting into cases.

Check yourself

2 of this module's 5 quiz questions. Pick your answers, then check them in the app, with an explanation for every question.

1. Solve: 4x − 7 = 13.

2. Solve: 5(x + 1) = 3x + 11.