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Algebra I to AP Precalculus · Module 3 of 14

Solving Linear Inequalities

One-variable, multi-step, compound, and absolute value inequalities — and when to flip the sign.

One-Variable Inequalities & Number Lines

  • Solve like an equation using inverse operations; the solution is a range of values.
  • Graph with an open circle for < or > (the endpoint is not included) or a closed circle for ≤ or ≥ (the endpoint is included), plus a ray.
  • "At least" means ≥; "at most" means ≤; "more than" and "fewer than" are strict (>, <).
Worked example

Solve and graph: x + 4 > 9.

Solution. Subtract 4: x > 5. Graph: open circle at 5, ray pointing right.

Multi-Step Inequalities & the Flip Rule

  • Solve the same way as multi-step equations, with one exception: multiplying or dividing both sides by a negative number flips the inequality sign.
  • After every solve, check whether your last step multiplied or divided by a negative — if so, confirm the sign flipped.
Worked example

Solve −3x + 6 ≤ 18.

Solution. Subtract 6: −3x ≤ 12. Divide by −3 and flip the sign: x ≥ −4.

Common mistake: Forgetting to flip the inequality sign when dividing or multiplying by a negative is the #1 inequality mistake.

Compound Inequalities

  • "And" compound inequalities (e.g. −2 < x ≤ 5) require both conditions true at once; the graph is the overlap of both.
  • "Or" compound inequalities require at least one condition true; the graph is the union of both rays.
  • A three-part inequality like a < expression < b can be solved by performing the same operation on all three parts at once.
Worked example

Solve −7 < 2x + 3 < 9.

Solution. Subtract 3 from all three parts: −10 < 2x < 6. Divide all three by 2: −5 < x < 3.

Absolute Value Inequalities

  • |x| < a (a > 0) becomes −a < x < a — an "and"/between statement.
  • |x| > a (a > 0) becomes x < −a or x > a — an "or" statement that splits apart.
  • Isolate the absolute value first, exactly like absolute value equations, before rewriting.
Worked example

Solve |x − 2| < 5.

Solution. Rewrite as −5 < x − 2 < 5. Add 2 to all parts: −3 < x < 7.

Common mistake: "Less than" gives an "and" (between); "greater than" gives an "or" (splits apart) — mixing these up is the most common error here.

Check yourself

2 of this module's 5 quiz questions. Pick your answers, then check them in the app, with an explanation for every question.

1. Solve: 2x − 5 < 9.

2. Solve: −5x + 2 ≥ 22.